Question

Use the perfect square trinomial formuals to factor. Be sure to factor out any common factors.

16y^2-8y+1

Answer 1

well; the name of it seems rather author specific...

Answer 2

divide out the 16; and then complete the square

Answer 3

we have 16 = 4 * 4 and -4-4 = -8

so the factors are

(4y - 1)(4y-1)

or (4y-1)^2

Answer 4

16y^2-8y+1
-----------
16


y^2 -(1/2)y + (1/16) ; (1/2)/2 = 1/4, sqaure it

y^2 -(1/2)y +1/16 - 1/16 + 1/16 ; group it

(y^2 -(1/2)y +1/16) +(-1/16 + 1/16)

(y-1/4)^2 +0

Answer 5

16(y-(1/4))^2 perhaps ╠╬╩