Question

can anyone help me with a pythagrean therom problem

Answer 1

sure

Answer 2

ok so the length a is 1m and the hypotenuse is 2\[\sqrt{5}\]

Answer 3

\[a^2 +b^2 = c^2\]
\[1^2 + b^2 = 2^2\]

Answer 4

\[b^2 = 4-1\]
\(b = \sqrt{3}\) right?

Answer 5

hypotenuse is 2 \[\sqrt{5}\]

Answer 6

work it out, and ill show you where you are going wrong at... since I already see it :)

Answer 7

the hypotenuse is two square root of 5

Answer 8

ohhh... \(2\sqrt{5}\) is the hyp

Answer 9

yes

Answer 10

well :) that changes it some

Answer 11

b^2 = hyp^2 - a^2

\[b^2 = (2\sqrt{5})^2-1\]
\[b^2 = 4(5)-1\]
\[b^2 = 19\]
\[b = \sqrt{19}\]