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Mathematics 13 Online
OpenStudy (anonymous):

WHAT IS THE EQUATION SET UP TO SOLVE?

OpenStudy (anonymous):

Suppose the area of a rectangle is 122.8 m2 and the length is 14 m longer than the width. Find the length and width in meters of the rectangle.

OpenStudy (anonymous):

x(x+14)=122.8 wer x is the width .

OpenStudy (anonymous):

let the width be x m then length will be (x+14) x * (x+14) = 122.8 x^2 + 14x -122.8 = 0

OpenStudy (anonymous):

U find he roots of the above quadratic equation and use ONLY THE POSITIVE value because distance/length can never be negative

OpenStudy (anonymous):

so is it 6.107 then add 14 to other one?

OpenStudy (anonymous):

what would the answer be?

OpenStudy (anonymous):

so the width is 6.07 and length is 20.07

OpenStudy (anonymous):

yea...

OpenStudy (anonymous):

better use 6.08 and 20.08

OpenStudy (anonymous):

ok sweet!

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