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Mathematics 6 Online
OpenStudy (anonymous):

find the exact value of the experssion cos^-1zero

OpenStudy (anonymous):

OpenStudy (anonymous):

pi/2

OpenStudy (anonymous):

got it?

OpenStudy (anonymous):

how did u get that

OpenStudy (anonymous):

cos(pi/2)=0 so the inverse means that...its right

OpenStudy (anonymous):

you are looking for a number (angle) between 0 and \[\pi\] whose cosine is 0. that is the one

OpenStudy (anonymous):

OpenStudy (anonymous):

trig cheat sheet here will find it for you http://tutorial.math.lamar.edu/cheat_table.aspx

OpenStudy (anonymous):

thank u

OpenStudy (anonymous):

gotta be last one because of the absolute value signs!

OpenStudy (anonymous):

how sure r u

OpenStudy (anonymous):

was i wrong ?

OpenStudy (anonymous):

no just asking

OpenStudy (anonymous):

it does say absolute value right? absolute value cannot be negative. must be above the x axis yes?

OpenStudy (anonymous):

@ brackett i was answering her second post, the graph above

OpenStudy (anonymous):

see tha range for cos inverse function is [0,pi] , so in this interval cos becomes 0 only at pi/2.

OpenStudy (anonymous):

OpenStudy (anonymous):

thank u

OpenStudy (anonymous):

u still there

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