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integral (3x^2 +x+4)/(x^3+x)
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\[\int\limits (3x^2 +x+4)/(x^3+x)\]
(3x^@+x+4)/[x(x^2+1)]=a/x+bx/(x^2+1)
find a,b
well, I dont know when to use Bx. can you please explain it?
i used Bx + C and got a result that checks out i got 4 / x^2 + 1 /(x^2 + 1) - x /( x^2 + 1)
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when ur denominator is a quadratic then use bx+c
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