Question

HOW MANY NUMBER CONSISTING OF TWO DIGITS CAN BE FORMED FROM 2,3,5,7.EACH INTEGER IS TO BE USED ONLY ONCE?

Answer 1

12

Answer 2

4*3=12

Answer 3

HOW?

Answer 4

for the 1st digit you have 4no.s u can put
and for the 2nd one u have only 3 cause u can't put the one u have put in the 1st 1 :)
Get it?

Answer 5

SORRY.CAN U PLZ DO IT IN STEPS?

Answer 6

w8 :)

Answer 7

OK

Answer 8

ANGELA?????????????????

Answer 9

a sec plsssss

Answer 10

for the 1-st digit u can choose one of the no.s given(2;3;5;7) and for the 2nd digit are left only three no.s from which u can choose to put in there cause you can't put the same didgit twice
EX: for the 1st digit you choose to put 3 and then for the 2nd digit you have left only 2,5,7
so 4*3=12

Answer 11

4 Pick 2; 4P2 = 4*3 = 12

Answer 12

4!/2! = 4P2 = 12 as well :)

Answer 13

See the attcch. maybe u'll understand