I need help with this work sheet someone helped me with some of the stuff but i need help plugging in the values to these A) use Pythagorean Theorem: d^2=a^2 + b^2 B) A= a*c C) V=1/2 * a*b*c D) surface area = sum of all surfaces: 2(1/2 ac)+dc+ac+bc Please help me
b=8; a=8; c=12
what part are you needing help with?
Everything I don't understand it, Im really confused can you please help me
well; lets start with the easier ones: A = a*c A = 8*12 ; what is the value for A then?
96?
is that a guess? :) yes, 8*12 = 96
yes that was a gues lol
V = (1/2) * a*b*c V = (1/2)* 8*6*12 ; what is the value for V?
just work it left to right what is (1/2)*8= ?
is it 12? im confuesd on this part
\[\frac{1}{2}*\frac{8}{1}=\frac{8}{2}\] what is 8 divided by 2 = ?
4
good; and 4*6 = ?
24
good; and the last part of it is: 24*12 = ?
288
yep :) so V = 288 right?
yes lol
Sa = ab+dc+ac+bc Sa = but we dont know d yet; so lets hold that one d^2 = a^2 + b^2 d^2 = (8)(8) + (6)(6) ; what is the value for d^2?
100?
good d^2 = 100 ; lets take the square root of both side to find 'd' sqrt(d^2) = sqrt(100) d = ?
is it 10?
it is :)
so we now have all the values needed for the Sa. a = 8; b=6; c=12; d=10
Sa = ab + c(a+b+d) Sa = 8(6) + 12(8+6+10); what is Sa ?
84
let me dbl chk that: Sa = 8(6) + 12(8+6+10) Sa = 48 + 12 (24) Sa = 48 + 288 Sa = 336
okay i see, can we do the first one now A) use Pythagorean Theorem: d^2=a^2 + b^2
there is one part that is off; and that the area of the triangular base; you read it wrong.... it wants to know the area of the triangle part
Yes; A) = 10 , we worked thru all these already right?
oops forgot lol, can you help me with another problem?
part B) wants to know: A = (1/2) *a*b A = (1/2) * 8 * 6; what is A?
24
very good :)
write up another question on the left to see if others can help you out as well :) thnx
okay
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