There are six black socks, six blue socks, 12 white socks, and four patterned socks in the drawer. What is the probability of pulling a blue sock, replacing it, and then drawing a patterned sock out of the drawer? Last question for the day my brain is done. I know this isn't hard but I just can't get it.

Question

There are six black socks, six blue socks, 12 white socks, and four patterned socks in the drawer. What is the probability of pulling a blue sock, replacing it, and then drawing a patterned sock out of the drawer?  Last question for the day my brain is done. I know this isn't hard but I just can't get it.

anonymous · Answer

probability is just how many divided by total number. 
For blue, it's 6 (blue ones) divided by (6 black+6 blue +12 white + 4 patterned) 
For patterned is 4(patterned) divided  by total. 
BUT since you want the probability of BOTH things happening you just multiply the two results.

anonymous · Answer

P(blue socks) = 6/28 = 3/14

since socks is replaced, the total remains 28
so P(patterned sock) = 4/28 = 1/7

anonymous · Answer

6/28 TIMES 4/28
or 24/784 which I'm sure you can simplify more.

anonymous · Answer

Thank You

anonymous · Answer

6/28 TIMES 4/28
or 24/784

anonymous · Answer

3/10
13/60
2/45
4/9
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