A rock is thrown off of a 100 foot cliff with an upward velocity of 35 m/s. As a result its height after t seconds is given by the formula h(t)=100+35t-5t^2

what is the velocity after 6 seconds?

Question

A rock is thrown off of a 100 foot cliff with an upward velocity of 35 m/s. As a result its height after t seconds is given by the formula h(t)=100+35t-5t^2

what is the velocity after 6 seconds?

amistre64 · Answer

-5t^2?  thats a round off of 4.9 right

amistre64 · Answer

100+35(6)-5(6^2)

100+ 210 - 5(36)

310 - 180

anonymous · Answer

that's the height :/

amistre64 · Answer

should be, according to the equation

amistre64 · Answer

130 meters or so

amistre64 · Answer

your equation is off tho; 100 feet and traveling in meters aint gonna get you nothing but headache

anonymous · Answer

there's 2 parts to the problem, the first which is height (which = 130), second asking for velocity. That's the equation that I got =/

amistre64 · Answer

130 feet ?  or meters?  if its feet we need to convert it

amistre64 · Answer

if it starts at a cliff 100 meters up; then 130 is good

amistre64 · Answer

the velocity is just the first derivative of position

amistre64 · Answer

35-10t in this case; at t=6

anonymous · Answer

correct :]