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Mathematics 20 Online
OpenStudy (anonymous):

2y +y^2-xy -(xy_y+3y^2)

OpenStudy (anonymous):

Whats the xy_y is that correct?

OpenStudy (anonymous):

xy-y

OpenStudy (anonymous):

\[2y+y^2-xy-(xy-y+3y^2)\]ok so the issue here is removing the brackets which means the signs change

OpenStudy (anonymous):

2y+y^2 -xy-xy +y-3y^2

OpenStudy (anonymous):

yes now collect terms as in -xy-xy = -2xy

OpenStudy (anonymous):

2+1*y-y^2-xy-xy

OpenStudy (anonymous):

\[-2y ^{2} + 3y - 2xy\]

OpenStudy (anonymous):

The answer is \[-2y^2+3y-2xy\]

OpenStudy (anonymous):

as NyteLyte has it

OpenStudy (anonymous):

im sill working on it!!

OpenStudy (anonymous):

\[2y+y^2-xy-xy+y-3y2\]collecting terms\[(2y+y)(+y^2-3y^2)-(xy-xy)\]so\[(3y)(-2y^2)(-2xy)\]finally rearrange so the largest coefficient is first and that gives the answer above

OpenStudy (anonymous):

thanks Kevsturge and Nyte Lyte

OpenStudy (anonymous):

okey.. gudluck..

OpenStudy (anonymous):

Harkirat.. false? please to correct :)

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