Question

If the probability of seeing moose in a day in a certain region of Alaska is 0.74, what is the probability of not seeing any moose in a day there?

Answer 1

probibility is out of 1

Answer 2

so 1- chance of seeing= chance of not seeing

Answer 3

i have 4 options. .74 .26 1.26 -.74

Answer 4

what do you think?

Answer 5

In a more formal way :
p(x) = probability of event x.

Given Omega the universe of possible outcome, P(Omega) = 1.
Given P(Moose) = 0.74, the complementary event "Not seeing moose" is by definition :
P(Not moose) = P(Omega) - P(Moose).
P(Not moose) = 1 - 0.74.
P(Not Moose) = 0.26

Answer 6

.-74