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log(x) + log(x-15) = 2
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u want what?
Solve logx+log(x−15)=2.
I don't know the answer
can u help me
log(x(x-15))=2, using log rule
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Use the identities of logarithms to rewrite it as: log(x(x-15))=2 Then raise everything to the 10 (I'm assuming you mean log base 10). x(x-15)=10^2 x^2-14x=100 x^2-14x-100=0 Use quadratic formula.
x(x-15)=10^2......log has base 10
thanks
No problem :P
u are very kind
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Use the identities of logarithms to rewrite it as: log(x(x-15))=2 Then raise everything to the 10 (I'm assuming you mean log base 10). x(x-15)=10^2 x^2-15x=100 x^2-15x-100=0 x^2-20x+5x-100=0 x(x-20)+5(x-20)=0 (x-20)(x+5)=0 So, x=20 or -5
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