-3x^2+4y^2-(5x^2-7y^2-1) now i came up with the answer of 32
-3x^2+4y^2-(5x^2-7y^2-1)=-3^2+4y^2-5x^2+7y^2+1=-8x^2+11y^2+1
How did you get 32? O.o
-3x^2+5x^2 (4y^2-7y^2
no u don't multiply them...u just add and subtract those just as with natural no.s
Bella is it minus before the bracket?>
yes thats what it looks like
\[11y^2-8x^2+1\]
then u don't have to multiply anything -3-5=-8 right? (integers) u don't have these u have -3x^2=5x^2=-8x^2
yes its definitaly minus
so it's =-8x^2+11y^2+1
now these are to the 2nd power i couldn't figure out how to type it in
write it by using the blue button below ''equation''
Yes it's \[11y^2-8x^2+1\] because \[(-3x^2-5x^2)(+4y^2+7y^2)+1\]Then rearrange so the highest coefficient is to the left giving the above
The trick is to change the sign of all the terms in the bracket when removing them thus the terms in the bracket become:\[-5x^2+7y^2+1\]
thanks angela i never thought about using that
Lol :P:P
okay Kevsturge this makes sense
so the answer is 25 then and not 32
how did you get 25?
Bella can u pls write the problem as it is written in ur book? this way we may help u better :)
okay i am lost am adding here or subtracting
okay one minute
Ah, I am missing something lol
\[-3^2+4y ^2-(5^2-7y ^{2}-1)\]
3x sory
and 5x
Sure does this equal 0 or something otherwise I cannot get an answer to this other than to collect the terms.
i am starting to wonder the same thing
Does the question say solve for x or y or something else?
so then it's the same answer we gave u if it is...\[-3x^2+4y^2-(5x^2-7y^2-1)=-3x^2+4y^2-5x^2+7y^2+1=-8x^2+11y^2+1\]
sorry got to go, will be back later..
bye :)
omg its after 2pm i have been so caught up thks guys i have to get ready for work i will be back later man
tks Angela i couldn't have figured this one out
You're welcome :):) Have a gr8 day :):)
will you be on later tonight
I don't think so...I have to study conics :(:(:( I'm very behind :(:( Sorry....other ppl will help you :):)
okay tks have a bless one
u 2 :)
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