Question

a particle in the xy-plane starts at the point (4,2) and moves along the curve y= sqrt(x) to the point (0,0) and then returns along the same curve to point(1,1). use a single vector-valued function to represent the path of the particle over a single interval (for the parameter). dont forget to give the interval for the parameter.

Answer 1

x=t^2 / 4
y=t/2

Answer 2

interval?

Answer 3

t goes frm 4 to 0 on first trip
from 0 to 1 on the second

Answer 4

please :)

Answer 5

isnt the (t) function suppose to be continuious?

Answer 6

isnt this continuous?

Answer 7

i think it should be 0 to 2 for 2nd trip: 2^2/4 = 1, 2/2 = 1

Answer 8

oh ys..my bad

Answer 9

and i agree it is continuous

Answer 10

im sorry i ment i thought that there should be one interval for both equations