In order to do pathygreom therom how do i know which is A,B,C of the triangle...?
the diagram tells you; or the problem tells you
dont get hung up on the 'names' of the variables; just know what the pythag meas
The shortest side is A, the side perpendicular to that is B, and the diagonal is C.
leg^2 + leg^2 = hyp^2
Here is the problem... maybe this whill help out with my question a little
this is the application of the law of cosines
But dont i need to find out the other side in order to do law of cosines..?
ohh nevermind your right!!!! :]] thankss
the third side is: 3rd side = \(\sqrt{6^2+10^2 -(2*6*10*cos(80))}\)
once you have that sides; you can law of sine it to ge the angles
thats the c^2=a^2*b^2-2(a)(c)cos80 yea :] but couldnt i use pathygreom therom for this ...
well, that IS the pythag thrm, or better; the pythag thrm is the law of cosines when the angle = 90
what happen when cos(90) is used in the law of cosines?
since you only know one angle, and it aint 90; pythag aint gonna help you out is it
ohh well i guess that explains it alot i just use it all the time no matter what the circumstance is if i only have two angles i usually just do pathagreom theroem though im always wrong i never know why youve been much help as always to me thank you !
:) youre welcome
Join our real-time social learning platform and learn together with your friends!