Question

Write the slope-intercept equation for the line that passes through (-2, 3) and is perpendicular to 2x – 9y = -12
please show work!

Answer 1

y = 3 = -9/2 (x+2)

Answer 2

-9/2 is the slope
y = -9/2x+m
3 = -9/2(-2) +b
b = -6
y = -9/2x-6

Answer 3

y - 3*

Answer 4

-b/a = slope of perp; 9/2

y = mx -mPx + Py; P(-2, 3)

y = 9/2 x -(9(-2)/2)+3

y = 9/2 x +9+3

y = 9/2 x +12 maybe?

Answer 5

the slope of the given line is -a/b (a = 2, b = -9)
the slope of a line perpendicular to a line with slope m is -1/m
so the slope of the line perpendicular to the given line is -1/(-a/b) = b/a = -9/2
then substitute this slope in the slope intercept form
y = mx+b
substitute the point and the slope you found and find b