Write the slope-intercept equation for the line that passes through (2, -2) and (-1, 10) please show work!
i don't understand what to do
y=-4x+(10/4)
how did you get y=-4
to find m. which is slope of the form Y=MX+B \[m=\frac{y _{2}-y _{1}}{x _{2}-x _{1}}\]
over three, down twelve same as over one down 4
\[m=\frac{10-(-2)}{-1-2}\] \[m=\frac{12}{-3}\] \[m=-4\]
now to find b. Just plug into the equation \[y=-4x+b\] the x and y and solve for b
from -1 to 2 is three steps to the right on horizontally. from 10 to -2 is twelve steps down. over 3 down 12. same as over 1, down 4. that explains the -4 as the slope. (- because down)
i tend to get my xs and ys misplaced so I perfer stacking and subtracting .... (2, -2) -(-1, 10) --------- 3,-12; slope = y/x = -12/3 = -4
y = -4x -(-4.2) -2 y = -4x +8-2 y = -4x +6
keebler you got this?
yes
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