Question

stephanie has the following scores on her algebra tests: 85, 92, and 71. What score must she earn on her fourth test in order to have an average of 80 or above?

Answer 1

Finding the average of a set of data is found by adding up all the data and dividing it by the amount of data that you have. In this case, that would be:

(85 + 92 + 71 + x) ÷ 4 = 80

x = The minimum score Stephanie needs to save her from getting a C in the algebra class.

From there, it's just a solve for x problem.

(85 + 92 + 71 + x) ÷ 4 = 80

Multuply each side by 4.

(85 + 92 + 71 + x) = 320

Simplify the left side.

248 + x = 320

Subtract 248 from both sides.

x = 72

So, Stephanie needs at least a 72 on her fourth test to get a B in the class. Knowing her previous scores, it shouldn't be that hard as long as it's nothing like her third test.

Answer 2

lol tks alot

Answer 3

No problem. :D