Question

Q-12 Find the angle of elevation of the sun when a 6m high pole makes shadow of length 2squrt3m on the horizontal plane.
a. 300 b. 450 c. 600 d. 900

Answer 1

tan-1(6/2sqrt(3))

Answer 2

you should write "degrees"

Answer 3

c 600 degrees :)

Answer 4

I mean the asker

Answer 5

"60 degrees" , not 600

Answer 6

:P

Answer 7

can u plz draw

Answer 8

no, im sure that you are capable enough to pick up your own pencil and paper and draw a picture. you really dont need anyone to hold your hand in doing that

Answer 9

its fairly simple lol

Answer 10

lol.... cute pic ;)

Answer 11

but its not to scale.... draw it again ..

Answer 12

tan-1(6/2squrt3) is it a formula?

Answer 13

no, it is an operation. just like + or / is an operation

Answer 14

tan-1(opp/adj) would be a formula

Answer 15

u mean perp/base

Answer 16

tan(a) = m/n

tan-1(tan(a)) = tan-1(m/n)

a = tan-1(m/n)

Answer 17

perp/base is a suitable interpretation for this problem yes

Answer 18

it is tan inverse?

Answer 19

it is :)

Answer 20

ok ok ok thanks amitre 4 ur humble response

Answer 21

youre welcome :)

Answer 22

in the end the answer wil b squrt3 yes?

Answer 23

in the end; the answer is 60 degrees

Answer 24

u dnt know what ur doing :|

Answer 25

me? lol .... you might be right

Answer 26

remember u are meant to learn from this site, not just get answers and

Answer 27

no, was talking to the asker

Answer 28

i mean that then tan-1 (squrt3)=60deg

Answer 29

I can tell some people on this site are only after answers.

Especially when they say things like "is that the final answer" , because that means that you are sort of only after the final answer and you didnt understand the reasoning and working out.

Answer 30

close .... \(\tan^{-1}(6/(2\sqrt{3}))=60^o\)

Answer 31

ok amister

Answer 32

.... and yes; tan-1(sqrt(3)) does = 60 degrees; but i was thinking in the context of the problem posted