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write each expression as the sum or difference of two log functions containing no exponents. 36) log5 (x2/square root of x +4))
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2logx-1/2log(x+4)
i guess 5 written with log is the base
yeah 5 is the base
ok,
so 2log(x-1)/2log(x+4)
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no
\[\log{ {x^2}\over \sqrt{x+4}}\]
this is what u r given.ok?
=log x^2- log[sqrt(x+4)]
2logx-(1/2)log(x+4)
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yeah but there is a 5 next to the log on the right
that would be there
its a base
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