Question

hey!How do you find the equation of the tangent line (x-1)^2=6(y+2) @(-5,4)....the derivative of the given eqn is 1/3x-1/3 btw:)

Answer 1

you wanna derive this?

Answer 2

(x-1)^2=6(y+2)

Answer 3

i already did that..n the deriv is the slope right..jus wonderin wat u do with the given point to find the equation at that point

Answer 4

if the derivative is what you posted; then input (x=-5) and solve to get the slope for your line

Answer 5

y-4 = f'(-5) (x+5)

Answer 6

ohh...got it! i got y-4=-2(x+5):)

Answer 7

that looks to be right :) good job

Answer 8

thank u so much again!:) u rock