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i know this ones supposed to be really easy but i want to make sure i did it right.Convert to rectangular form,r=-3sin(theta)
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r^2 = 9sin^2 (theta)
so x^2 + y^2 = 9y^2/ (x^2 + y^2)
r=-3sin(theta) r^2 = -3 rsin(t) x^2 + y^2 = -3y
is the answer x^2+y^2-3y=0?
x^2 + y^2 +3y = 0 is what I get, if it done right
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ohh +3y..righttt..got it! thanks again!
wait
x^2 + y^2 + 3y = 0 means r^2 = -3rsin(theta)
ur question says -3sin(theta) not -3rsin(theta)
yeah
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sooo...wat do i do
look at wht i wrote and simplify it
no its right
its fyn leave it
ohk:)
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