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Find dy / dx by implicit differentiation. xy + 5x + 3x^2 = 5... I got y'=(-y-5-6x)/x...but i got stuck
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[xy]' = x'y + xy' [5x]' = 5 [3x^2]'=6x [5]' = 0
x'y + xy' +5 + 6x = 0 y' = (-5-6x -y)/x
yes...i got that steps i took all of the derviatives
where you stuck at? you found the derivative
sure looks good to me!
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that y'=(-5-6x-y)/x
but how do i finish it?
by inserting whatever point they give you to fill in x and y
you have a curve and have decided that y is a (implicit) function of x. since you did not solve for y in terms of x your answer must have a y in it. you are done
haha there is no point i wish there was
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then y' = what it equals and you are done with it
o ok..so i had the answer right then
yes
ok thanks
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