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Show that f(x) = |x-1| is not differentiable at x=1
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if x-1>0 => x>1, then f(x)=x-1 => f'(x)=1 if x-1<0 => x<1, then f(x)=-(x-1) => f'(x)=-1 therefore f is not differentiable at x=1
limit from the right doesnt match the limit from the left; so limit does not exist; no limit, no derivative
right
thanks guys.
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