2x-6y=30 3x-9y=-27 Solve the system of equations by graphing ( i don't need the graphing done, I just need a walk through of how to solve this)
okay to do this first that the 1st eq'n 2x -6y = 30 and graph it. I would graph this line by finding the x and y intercepts x int (let y = 0): (15,0) y int (lets x = 0): (0,-5) next, take the second equation 3x-9y=-27 and graph it as well x int (let y = 0): (-9,0) y int (lets x = 0): (0,3) wherever the lines meet is the sol'n
How did you come up with the 15 and -5??
for 15, the x intercept occurs when y = 0. Sub y = 0 into the equation -2x -6(0) = 30 -2x = 30 x = -25 the y intercept occurs when x = 0. Sub x = 0 into the equation -2(0) -6y = 30 -6y = 30 y = -5
ooohhh I see...okay, so since there is more than one ordered pair, that means there is more than one solution?
The solution will be one point on the graph (x,y) where the two lines intercept. The lines should only cross once. The (15,0) and (0,-5) are just two points so you can graph the first line.
OOOHHHHHHH DUH!!! lol
:)
my graph should look like an X ?
would the ordered pair be (0,3)
when these two equations are graphed, they are parallel; which means no solution.
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