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what is the standard form of equation line passing through (5,-3) with a slope of -3
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Ok, y = 3x + C -- line with slop of 3. Let's find C: -3 = 3*5 + C => C = -18. And the standard form is y = 3x - 18.
A linear equation is written in general terms y = mx + c Where m is the gradient of the line or its slope and c is the point of intercetion on the y axis. Given the coordinate pair and the slope substitute for m, x and y and start to build the equation. y = mx + c becomes... -3 = (-3)(5) + c therefore... -3 = -15 + c adding 15 to both sides... 12 = c And so the equation for this line is... y = 12 -3x
Nikita I think you forgot the negative in the value of m.
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