Question

lxl-2=3

Answer 1

x = +- 5

Answer 2

lol lx+12l =8

Answer 3

I dont know how to do the absolute value symbols, so bear with me

Answer 4

|x+12| = 8 is the same as | x -(-12)| = 8, therefore x is either -20 or -4.

Answer 5

simply, |a - b| is the distance between a and b on the real axis.

Answer 6

|6-x|=10

I know one of them is 4 but whats the other T_T

Answer 7

\[|x+12|=8\] solve two equations
\[x+12=8\] or
\[x+12=-8\] first one gives
\[x=-4\]
second one gives
\[x=-20\]

Answer 8

lol fail. I forgot that was a negative

Answer 9

lxl-3=6

Answer 10

\[|6-x|=10\] same as
\[|x-6|=10\]
solve
\[x-6=10\] or
\[x-6=-10\]

Answer 11

convince yourself that
\[|a-b|=|b-a|\] so you do not have to deal with the annoying
\[|6-x|\] just change to
\[|x-6|\]

Answer 12

whered you get the 10?

Answer 13

you wrote
\[|6-x|=10\] i just changed it to
\[|x-6|=10\]

Answer 14

lol.

Thought we were working on this one D:
lxl-3=6

Answer 15

this one is easier. this one is
\[|x|=9\]
making
\[x=\pm 9\]

Answer 16

okay for lx+4l=3 you would make it 4+x=-3 and 4=x=3, correct?

Answer 17

that last part was supposed to say 4+x=3