Question

use the quadratic formula to solve 2y=4y^2-6

Answer 1

first put it in the form ax^2 + bx + c = 0
i.e 4y^2 -2y -6 = 0
here a = 4, b = -2 and c = -6

Answer 2

quadratic formula is
\[- b \pm \sqrt{(b ^{2}}-4ac)/2a\]

Answer 3

so

- (-2) +/- root[(-2)^2 - 4*(4)*(-6)] 2 +/- root[4 + 96]
x = ------------------------------- = --------------------
2 * 4 8
2 +/- root[100] 2 +/- 10
x = --------------- = ---------
8 8

Answer 4

so
2 + 10 2 - 10 12 -8
x = -------- or -------- = ----- or --------
8 8 8 8

so x = 3/2 or x = -1

Answer 5

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Answer 6

\[2y=4y^2-6\]
\[4y^2-2y-6=0\]
\[2y^2-y-3=0\]
\[y=\frac{1\pm\sqrt{1-4\times 2\times -3}}{2\times 2}\]
\[y=\frac{1\pm\sqrt{25}}{4}\]
\[y=\frac{1+5}{4}=\frac{6}{4}=\frac{3}{2}\] or
\[y=\frac{1-5}{4}=\frac{-4}{4}=-1\]