Question

54x^-1/4= 5 solve x

Answer 1

what is the power of x? -1 or -1/4 ?

Answer 2

\[54x^{-\frac{1}{4}}=5\]?

Answer 3

yes

Answer 4

go ahead satellite

Answer 5

no idea.

Answer 6

ok divide by 54, take the reciprocal, raise to the fourth power

Answer 7

it will be +/-(54/5)^4

Answer 8

ok. ill explain how to do it.
instead of just give answer.

Answer 9

\[x^{-\frac{1}{4}}=\frac{5}{54}\]
\[x^{\frac{1}{4}}=\frac{54}{5}\]
\[x=(\frac{54}{56})^4\]

Answer 10

oops typo

Answer 11

52x^(-1/2) means 52/sqrt(x) = 20
then to solve for x, you multiply both sides by sqrt(x) and divide both by 20.
this leaves you with:
52/20 = sqrt(x)

then to solve for x, you square each side, giving:
(52/20)^2 = +/- X

so x=+/- 6.76 = +/- (169/25)

Answer 12

it confuses me when the number comes out with X^2/3,,, i mean i can solve number power of a solid number, but when there is power of something that has to divide by something,, it confuses me

Answer 13

ok. x^(2/3) is equivelant of x^2 * x^(1/3). when you take a variable to 1/3 or 1/<some number> you take the cubed root <nth root>

Answer 14

last question,,, 54x^2/3 = 20

Answer 15

when it is negative, it means take the reciprocal. (AKA flip the variable to denominator if in the numerator, or vise versa)

Answer 16

OK:
\[54x ^{2/3} = 20\]

\[x ^{2/3} = 20/54\]

then square both sides:

\[x ^{1/3} = (20/54)^{2}\]
then take the cubed root of both sides:
\[x = \sqrt[3]{(20/54)^{2}}\]

Answer 17

alright thanks, i got it,, it is more clear in this way

Answer 18

However; because X was squared, the answer can be both positive or negative,
EX:
\[(-6)^{2} = (6)^{2} = 36\]

Answer 19

yeah i know this one but just when the power is divided by something, it confuses me