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OpenStudy (anonymous):
When you complete the square and divide the b- term by two, do you include the coefficient? 6x/2 Would that be 3x or just 3?
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OpenStudy (anonymous):
it would be 3
OpenStudy (anonymous):
No, you do not include the coefficient. However, if the term is +6x, what you do is, take half the coefficient then square it, then add to both sides of the equation.
OpenStudy (anonymous):
because you are starting with \[x^2+6x+c\] \[(x+3)^2=-c+9\]
OpenStudy (anonymous):
EDIT: first time using coefficient I meant to say variable ><
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