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OpenStudy (anonymous):
i wanna make sure i did it correct
OpenStudy (anonymous):
plug and chug.
\[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
OpenStudy (anonymous):
ok we get
a = 10
b = 2
c = -3
OpenStudy (anonymous):
best to write them down and then you know what you are substituting
OpenStudy (anonymous):
less likely to screw up
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OpenStudy (anonymous):
What is the answer you got? We can tell you if its right or not, This is the 5th one of these ive seen from you :P maybe we can teach you instead of give answers. Again, it is in standard form of \[ax^2 + bx + c = 0\] now, just plug and chug into the quadratic equation :)