10m^2+2m-3=0 use the quadratic formula
i wanna make sure i did it correct
plug and chug. \[x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
ok we get a = 10 b = 2 c = -3
best to write them down and then you know what you are substituting
less likely to screw up
What is the answer you got? We can tell you if its right or not, This is the 5th one of these ive seen from you :P maybe we can teach you instead of give answers. Again, it is in standard form of \[ax^2 + bx + c = 0\] now, just plug and chug into the quadratic equation :)
\[\frac{-2\pm\sqrt{2^2-4\times 10\times -3}}{2\times 10}\]
ok so -2+- square root 2^2-4(2)(-3)/2(10)
i get \[\frac{-1\pm\sqrt{31}}{10}\]
oh wait i am sorry you are right
you are correct.
\[-2\pm \sqrt{28}\]/20
get \[\frac{-2\pm\sqrt{124}}{20}\]
think you messed up with \[b^2-4ac\] again
\[2^2-4\times 10\times -3\] two minus signs so it is plus
\[4+120\]
124
-2 +- square root 124/20
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