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OpenStudy (anonymous):
Determine
n(A)
n(B)
P(A)
P(B)
P(A|B)
P(B|A)
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OpenStudy (anonymous):
its a Venn Diagram..
40 is A in one circle 80 is B in another one. and 10 in Both..
OpenStudy (amistre64):
like this?
OpenStudy (anonymous):
yea...:)
OpenStudy (anonymous):
so i have to determine the following i posted..
OpenStudy (amistre64):
total is 130; for the probability stuff
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OpenStudy (anonymous):
would that be the one that have a P in front of them?
OpenStudy (amistre64):
yes :)
n(A) = 40+10 = 50
n(B) = 80 + 10 = 90
P(A) = 50/130
P(B) = 90/130
P(A|B) = ?
P(B|A) = ?
A given B terminaology I gotta look up to refresh meself
OpenStudy (anonymous):
are you a ex teacher? cuz you seem to know your stuff great.
OpenStudy (amistre64):
im a student, getting my degree in math :)
\[P(B|A)=\frac{P(AnB)}{P(A)}\]
OpenStudy (anonymous):
thats kewl. :)
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OpenStudy (anonymous):
I am going to school for cyber crime investigator and I HAVE to take these math classes.. which I am completely STUPID in..
OpenStudy (amistre64):
P(AnB) = 10/130
P(B|A) = 10/130
-------- = 10/50
50/130
P(A|B) = P(AnB)/P(B) = 10/90
OpenStudy (amistre64):
well, you might wanna reduce these fractions :)
n(A) 50
n(B) 90
P(A) 5/13
P(B) 9/13
P(A|B) 1/9
P(B|A) 1/5
OpenStudy (anonymous):
ok
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