I have like 7 problems I need help with but I would have to email them because theyre are graphs attatched...does anyone feel like being a HUGE help??

Question

I have like 7 problems I need help with but I would have to email them because theyre are graphs attatched...does anyone feel like being a HUGE help>>??

anonymous · Answer

You can attach files here. Just do 'em one by one.

anonymous · Answer

which of the following is the equation of the horizontal asymptote of the graph of f(x) = (1/3)^(x+2) -3

x = -2
x=0
y=1/3
y=-3

anonymous · Answer

y=-3

anonymous · Answer

To solve this, firstly, it asks for a horizontal asymptote, so the first two are out as they would give vertical ones. Next you need to set y=-3 in the equation, and so 0=(1/3)^(x+2), as you have to take logs to solve for x, and ln(0) is not defined, y=-3 is not defined
Hope this helps