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Mathematics 7 Online
OpenStudy (anonymous):

How do you solve something like: Charlie has 13 socks in his drawer, 8 blue and 5 green. He selects 5 socks at random. Find the probability that he gets a. Two blue socks and three green socks

OpenStudy (anonymous):

type in 8C2 multiplied by 5C3. c stands for combination. do you have a graphing calculator or do you have to do this by hand?

OpenStudy (anonymous):

I have to do it by hand.... :/

OpenStudy (anonymous):

i'm sorry. in that case, the formula for a combination is n!/k! (n-k)! in the problem 8C2 x 5C3, you have to do each separately, then multiply them afterwards the 8 is the n, and the 2 is the k so 8!/2! (8-2)! (8! represents 8x7x6x5x4x3x2x1) you get 40320/2x720 or 28 do the same for the other combination, you get 10 28 x 10 = 280. this number is 280 out of 1287 (the total number of combinations possible)

OpenStudy (anonymous):

Thank you!

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