Question

How do you solve 2(x-3)^2=98 algebraically?

My answer key says the answer is 10, but I think it is wrong

Answer 1

No, its right, Start by dividing both sides by 2, then you get (x-3)^2=49
Then square root both sides and you get (x-3)=7
Then add 3 to both sides and you get x=10

Answer 2

thanks so much

Answer 3

Anytime :)

Answer 4

\[2(x-3)^2=98\]
\[(x-3)^2=49=7^2=(-7)^2\]
\[x-3=7\quad\vee\quad x-3=-7\]
\[x=10\quad\vee\quad x=-4\]