Question

I got 60 but then I saw how my teacher had solved it and she had got 75,I asked her today for the same q. and she got 57......What's the answer? Oo
How many even,three digit numbers can be formed by using no.s from A={0;1;2;3;4;5} ****without repetition*****

Answer 1

\[3\times 4P2?\]

Answer 2

I would say the three digit numbers that can be formed are \(6(5)(4)=120\). The even numbers are then \(60\). Not entirely sure though.

Answer 3

I got 5*4*3=60
It can be even only if the last digit is 0,2, or 4 so 3 choices
then the 1st digit can't be 0 so 4 choices
and 5 for the 2nd digit...tha'ts wht I thought....

Answer 4

the last digit has to be a either a 0 or 2 or 4 for it to be an even number.
so 3 ways you can choose the last digit. next you have 5 ways to choose the second last digit. next you have 4 ways of choosing the first digit.
giving you 4*5*3=60

Answer 5

Oh sorry, should be \(3\times 5P2\) which as you say, equals 60.

Answer 6

Yahoo!!! :):):) I'm smarter than my teacher :P:P:P:P
Thanks guys :):):)

Answer 7

always challenge something if it doesnt make sense and you are welcome :)

Answer 8

Probably best not to say that to her :P

Answer 9

Hahha lol .....She can't do any harm to me now,I'm done with hs :P:P:P:P :)

Answer 10

I wonder how she got 75.

Answer 11

hold on a minute. 60 is incorrect.

Answer 12

she did 5*5*3

Answer 13

but today she did 5*4*1+4*4*1+4*4*1=57

Answer 14

why is incorrect Dhatraditya?

Answer 15

That's strange, if you could repeat numbers I guess it would be 6*6*3 but I don't know where 5*5*3 comes from.

Answer 16

52 not not 57 sorry**

Answer 17

52 is right

Answer 18

Why?

Answer 19

Is the number 012 a 3-digit number?

Answer 20

OMG!!! Which 1's right?

Answer 21

with 0 as the last digit, you can have 5 numbers to choose from for the middle digit and 4 numbers to choose from for the first digit.
with 2 and 4 as the last digit, however, you have 5 numbers to choose from for the middle digit, but you dont have 0 as an option to be the first digit, because then it would be just a two digit number.

Answer 22

no it's not that's why there r left 4 no.s 4 the 1st digit

Answer 23

Lets consider the case where the ending digit is zero
The no of cases are 5 x 4 x 1 = 20

Now lets consider the cases where the ending digit is 2 or 4
The no of cases are 4(excluding zero) x 4 x 2 = 32

Totals 32

Answer 24

huh? 1st 75 then 57 then 60 now 32????????

Answer 25

oh srry 52..i meant 20 + 32

Answer 26

Probably 52 makes more sense....

Answer 27

yes it is 52

Answer 28

oh....so the final answer is 52....?

Answer 29

indeed..u understood the method?

Answer 30

Yea I did...thnx :):):)

Answer 31

no problems

Answer 32

him1618, why did you do 4x4x2 for the other two? the middle digit can still be 0

Answer 33

let me draw smth plsss

Answer 34

the middle 4 includes a ZERO
see the middle digit has 5 choices including zero, but one choice has already been used as the first digit, so actually only 4 ways remain

Answer 35

No repetition remember

Answer 36

012345 are 6 digits, so with one digit used up, 5 digits remain for the middle digit, including 0

Answer 37

but uve used one from 2 or 4 already to fill up the last digit havent u?

Answer 38

what I mean is, suppose you used 2 for the last digit, you still have 0,1,3,4,5 to choose from. that is 5 digits.

Answer 39

for the middle digit of course

Answer 40

uve already used 1 3 4 or 5 in the first digit..so that leaves u 4 choices

Answer 41

right right. I got it. :)

Answer 42

thanks

Answer 43

This is what Him meant i guess

Answer 44

yes

Answer 45

Thnx :):)

Answer 46

no prob :))))))))))