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Find the equation of the line passing through (6, -4) and parallel to the line with the equation 2x - 3y - 1 = 0.
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Parallel means same slope
2x - 3y - 1 2x-3y=1 -3y=-2x+1 y=2/3x-1/3 So the slope is 2/3
Let's use point-slope form your point is (6,-4) y-y1=m(x-x1) So let plug it in y-(-4)=2/3(x-6)
Being helpful and answering my question, unlike you who is just filling my question with useless sapm Go ahead, imranmeah91
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y-(-4)=2/3(x-6) y+4=2/3(x-6) y+4=2/3x -4 y=2/3x -8
I have 4 options: A: 2x - 3y - 24 = 0 B: 3x + 2y - 10 = 0 C:2x - y - 16 = 0 D: 2x - 3y - 18 = 0
y=2/3x -8 Multiply the whole thing by 3 3y=2x-24 2x-3y-24
Thankyou very VERY much!
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