Ask your own question, for FREE!
Mathematics 49 Online
OpenStudy (anonymous):

derivativate (sqrt16-x)

OpenStudy (anonymous):

\[\sqrt{16-x}\]

OpenStudy (anonymous):

is it (16-x)^2

OpenStudy (anonymous):

first you use the chain rule so take the derivative of 16-x, that is just -1 than multiply -1 with the derivative of the sqrt that is 1/2 * (16-x)^(-1/2) so the solution is: - 1/2 (16-x)^(-1/2)= -1/ (2 sqrt(16-x))

OpenStudy (anonymous):

when there is a polynomial like x^n than the derivative will be: n*x^(n-1)

OpenStudy (anonymous):

o ok cool thanks

OpenStudy (anonymous):

so here the sqrt mean 1/2 so sqrt x= x^1/2

OpenStudy (anonymous):

ok thanks : )

OpenStudy (anonymous):

no problem :-)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
WalmartBag: can someone pls give me a proxy
25 minutes ago 2 Replies 0 Medals
Breathless: womp
1 hour ago 0 Replies 0 Medals
Breathless: yo who wanna match pfp?
2 hours ago 11 Replies 1 Medal
Ylynnaa: This was long time ago lmk if u fw itud83dude1d
5 hours ago 17 Replies 2 Medals
abound: Wow question cove really fell off
7 hours ago 6 Replies 1 Medal
ayden09: chat i love black pink hehe i like jones to
7 hours ago 20 Replies 2 Medals
kamani7676: help
1 day ago 5 Replies 1 Medal
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!