Mathematics

OpenStudy (anonymous):
Simplify, step by step please: [(1/(x+h)^3) - (1/x^3)] / 15h

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OpenStudy (anonymous):
this is horrid...

OpenStudy (anonymous):
Agreed.

OpenStudy (anonymous):
are you talking about my question domian and range

OpenStudy (anonymous):
you have not given a function there prodgers

OpenStudy (anonymous):
the domain andrange of f (-2) of f(1)

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OpenStudy (anonymous):
for this one you need to make a common denominator for x^3 and (x+h)^3

OpenStudy (anonymous):
so what would be the answer I am so confused with this mess. I have not taken this kind of mathe in 20 yrs

OpenStudy (anonymous):
\[(x^3 - (x+h)^3 )/(x^3 * (x+h)^3)\]

OpenStudy (anonymous):
prodgers2, go back to your question and look at what I typed....

OpenStudy (anonymous):
so is that the range or the donmain

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OpenStudy (anonymous):
by the way is this for a limit?

OpenStudy (anonymous):
Nope, no limit

OpenStudy (anonymous):
and the above is still divided by 15h
(x+h)^3=x^3+3x^2h+3xh^3+h^3

OpenStudy (anonymous):
so the x^3 will cancel

OpenStudy (anonymous):
and the h too

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OpenStudy (anonymous):
\[(3x^2+3xh+h^2)/(15(x^3 * (x+h)^3)\]

OpenStudy (anonymous):
oh no, there is a minus sign in front of this

OpenStudy (anonymous):
yes and it is asking to write the answer in interval notation

OpenStudy (anonymous):
and I dont see how you can simplify it further

OpenStudy (anonymous):
\[[(1/(x+h)^3) - (1/x^3)] / 15h = 0 \] ???

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OpenStudy (anonymous):
Yes

OpenStudy (anonymous):
akiroso is that the range or domain?

OpenStudy (anonymous):
prodgers2, it's neither, this is not your problem.

OpenStudy (anonymous):
okkie dookie

OpenStudy (anonymous):
THANKS ANDRAS!!! XD