Question

Solve by completing the square:
\[3x^2 - 6x - 5 = 0\]

Answer 1

OK

Answer 2

\[3x^2-6x=5\]
\[x^2-2x=5/3\]
\[(x-1)^2=5/3 +1\]
\[x-1=\pm \sqrt{(8/3)}\]
\[x=1\pm \sqrt{8/3}\]

Answer 3

you failed to complete the square...

Answer 4

why?

Answer 5

completing the square means that you take b/2 and square it to get c...

Answer 6

I am pretty sure that I did what the question asked

Answer 7

completing the square is not shown in your work. you moved the 5 to the other side and divided by three. this is not completing the square

Answer 8

completing the square would start like: \[{-6 \over 2}, -3^2 = 9\]