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OpenStudy (anonymous):

to find the integral of x/[(9-(x^2))^1/2)], is it quicker to use the quotient rule of u substitution?

OpenStudy (anonymous):

* or, not of

OpenStudy (anonymous):

i'd use substitution

OpenStudy (anonymous):

should i substitute the x^2? i'm confused with how i should deal with the sqrt..

OpenStudy (anonymous):

no substitute u = 9-x^2

OpenStudy (anonymous):

is the answer -9+x^2 +c?

OpenStudy (anonymous):

no the answer is \[-\sqrt{9-x ^{2}}+c\]

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