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to find the integral of x/[(9-(x^2))^1/2)], is it quicker to use the quotient rule of u substitution?
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* or, not of
i'd use substitution
should i substitute the x^2? i'm confused with how i should deal with the sqrt..
no substitute u = 9-x^2
is the answer -9+x^2 +c?
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no the answer is \[-\sqrt{9-x ^{2}}+c\]
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