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rationalize the denominator \[14\sqrt{3}/3\sqrt{7}\]
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14 = 7x2 = sqrt7 x sqrt7 x 2
14=7x2 =sqrt7 x ssqrt7 x 2
\[10\sqrt{3} /3\sqrt{5}\]
express 10 in terms of 5 and take it from there
same thing as I explained above
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so is the answer\[2\sqrt{15}/3\]
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