Question

Can someone help me with finding the formula for P(x)?

The polynomial of degree 3, P(x), has a root of multiplicity 2 at x=3 and a root of multiplicity of 1 at x=-1. Another point on the polynomial is (4,-10).

Answer 1

(x+1)(x-2)^2

Answer 2

I know that part, it's going through the points I dont get.

Answer 3

sorry it is -1/2(x+1)(x-2)^2

Answer 4

ok, how do you find that?

Answer 5

the -1/2?

Answer 6

wouldnt it be (x-3)^2

Answer 7

with the rest

Answer 8

(x-3)^2(x+1)

Answer 9

substitute x =4 in (x+1)(x-2)^2 you get 20
but -10 is what you should get for x =4
so the constant multiplier has to be -1/2

Answer 10

constant =-2

Answer 11

OOOH!!! gotcha. I will try that.

Answer 12

no mathmajor, you are incorrect. constant is -1/2

Answer 13

hey, wait a minute. Why does (x+1)(x-3)^2 not work?

Answer 14

ur formula was wrong i believe

Answer 15

if you substitute 4 in that you get 5 times 1^2 = 5

Answer 16

I understand the -1/2 part, not thereal zeroes part.

Answer 17

oh right, I misread the question. mathmajor is right

Answer 18

i thought it had a multiplicity of 2 at x =2

Answer 19

lol i know what u did u saw the 2

Answer 20

instead of multiplicity 2 at x =3

Answer 21

Yes, butI put in -1/2*(x-3)^2(x+1) and It was incorrect. whats wrong with it?

Answer 22

Oh, got it

Answer 23

plug a 4 in and find multiplier

Answer 24

it is -2*(x-3)^2(x+1)

Answer 25

because the formula I supplied was wrong
f(x) = k(x-3)^2(x+1)
-10 = k (1^2) * 5
5k =-10
k = -2
so the correct answer is -2(x-3)^2(x+1)

Answer 26

thanks :)

Answer 27

np

Answer 28

dhat peace :) im hitting the bed

Answer 29

good night :)

Answer 30

I hear you, nite nite