28 men can finish the job in 60 days. At the start of the 16 day, 5 men were laid off and after the 45th, 10 more men were hired. How many days were delayed in finishing the job? Please explain, step by step.

Question

anonymous · Answer

really?  i am going to change my name to i hate math

anonymous · Answer

i am going to suggest this although there is probably a snappier way.  28 men in 60 days to one job so each man and do 
$$\frac{1}{28\times 60}=\frac{1}{1680}$$ of the job per day

anonymous · Answer

then the equation becomes 
$$\frac{15\times 28}{1680}+\frac{23\times 30}{1680}+\frac{33\times x}{1680}=1$$

anonymous · Answer

or if you prefer $$33x+1110=1680$$
and thus 
$$x=\frac{190}{11}=17.27$$so the total time was 45+17.27=62.27 and therefore the delay was 2 + (say 3) days

anonymous · Answer

from where did you base 33x+1110=1680?