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find the discrimiant
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the discriminant is b^2-4ac where a=8 b=18 c=-5 18^2 - 4(8)(-5) =484
a=-12 b=5 c=2 5^2 - 4(-12)(2) =121
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a=9 b=-6 c=-4 -6^2-4(9)(-4) =108
its asking me to find the solution for the last two
using the quadratic equation?
iive already work out the problem i just need someone to do it so i can see what they get
did you use the quadratic equation though?
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yes
for the 2nd to last = -5 (+or -) squareroot(121)/-24 so x = -1/4 or x = 2/3
last one 6(+or -) squareroot(108)/16 x = (1+root3)/3 or x = (1-root3)/3
did you get that?
yeah
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a=1 b=3 c=3 no solutions to the discriminant as it is negative ( what level maths are you at) therefore there is no solution
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