Mathematics OpenStudy (anonymous):

determine the natur of the roots OpenStudy (anonymous): OpenStudy (anonymous): OpenStudy (lalaly):

(2x+8)^2 =0 x= -4 and x=-4 OpenStudy (anonymous):

first one divide by 4 and get $x^2+8x+16=0$ then if you want the "nature of the zeros" compute $b^2-4ac=64-64=0$so there is one solution. meaning it is a perfect square namely $(x+4)^2$ and the solution $x=-4$ OpenStudy (anonymous):

second one $3x^2+12x-3=0$ $b^2-4ac=12^2-4\times 3\times -3=144+36=180$ so there are two real solutions OpenStudy (anonymous):

so solve write $x^2+4x-1=0$ $x^2+4x=1$ $(x+2)^2=1+2^2=1+4=5$ $x+2=\pm\sqrt{5}$ $x=-2\pm\sqrt{5}$

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