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Mathematics 38 Online
OpenStudy (anonymous):

please tell me if this is correct x+17 ----->0 x-20 {x/x<-17 or x>20}

OpenStudy (amistre64):

\[\frac{x+17}{x-20}>0\] is the question?

OpenStudy (amistre64):

we can multiply it all by x-20 to clear the fraction, but the might introduce extraneous results

OpenStudy (amistre64):

x+17 > x-20 17 > -20 .... that dint work out to good lol

OpenStudy (anonymous):

im looking for the easy way out

OpenStudy (amistre64):

the easy way out is if you have choices; to work them in the problem

OpenStudy (amistre64):

other wise; x+17 >0 means that x >-17 are there any restrictions on the bottom that will make >-17 go wrong?

OpenStudy (anonymous):

?

OpenStudy (amistre64):

<.........-17.........20............> - + + ; sign of the top - - + ; sign of the bottom -------------------------- + - + ; sign of it all this is how they interact top to bottom. {x| x<-17 OR x>20} is correct

OpenStudy (anonymous):

ty

OpenStudy (amistre64):

:) youre welcome

OpenStudy (a_clan):

this fraction will be positive when either both numerator and denominator are positive OR both are negative. 1. x+17>0 & x-20>0 i.e x>-17 and x>20 i.e. x>20 2. x+17<0 & x-20<0 i.e. x<-17 and x<20 i.e. x<-17 Hence the answer { x| x<-17 or x>20}

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