Question

how do you find the limit of lim x->5^+ of Ix-2I/x-2?

Answer 1

\[\lim_{x \rightarrow 5^{+}} \left| x-2 \right| / x-2\]

Answer 2

just use direct sub.

Answer 3

|5-2|/(5-2)=3/3=1

Answer 4

sryy..i meant limx→2+|x−2|/x−2

Answer 5

its not a 5..its a 2

Answer 6

if x-2>0 (x>2) then |x-2|=x-2
so |x-2|/(x-2)=(x-2)/(x-2)=1 for x>2
if x-2<0 (x<2), then |x-2|=-(x-2)=-(x-2)
so |x-2|/{x-2}=-(x-2)/(x-2)=-1 for x<2
since we are looking to the right of the 2, then we are looking at values near 2 that are greater than 2 so the limit is 1

Answer 7

ohhok..gotcha..thank u soo much!!