what is the equation of the line that is parallel to the line 3x+4y+6=0 going through the point (2,2)?

Question

anonymous · Answer

go get em

anonymous · Answer

btw did you see that i am now over 1000?  maybe i will catch up to amistre?

myininaya · Answer

3x+4y+6=0
4y=-3x-6
y=-3/4*x-6/4
y=-3/4*x-3/2
slope of this line is -3/4
so slope of any parallel line is also -3/4
so line has form y=mx+b
we know a ponint on this line (x=2,y=2)
2=-3/4*2+b
solve for b
2+3/4*2=b
so the equation of the line is 
y=-3/4*x+2+3/2

myininaya · Answer

yes satellite you will be the greatest