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Find the exact solutions to each equation for the interval 0
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Divide each side by sin x
so its cos x=0?
no cosx=1
which means that x=0 or 2*pi right?
wow.... 0<x<2pi... no = if that is the case => no solution
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the problem states that x is greater than or equal to 0. so i would assume its 0. i just couldnt add in the equal to symbol
next time type: >= or <= everybody will understand :) if <= then 2 solutions: 0 and 2pi
okay thanks for the tip and answer
welcome!
sinxcosx=sinx sinxcosx-sinx=0 sinx(cosx-1)=0 sinx=0 cosx-1=0 sinx=0 cosx=1 x=0 x=0 x=pi x=2pi x=2pi
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you guys missed a solution
isnt it just 0 and 2pi?
and pi
oh, alright thanks, would have missed that
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