Find the exact solutions to each equation for the interval 0

Question

Find the exact solutions to each equation for the interval 0<x<2pi. sin x cos x=sin x

anonymous · Answer

Divide each side by sin x

anonymous · Answer

so its cos x=0?

anonymous · Answer

no
cosx=1

anonymous · Answer

which means that x=0 or 2*pi
right?

anonymous · Answer

wow.... 0<x<2pi... no = 
if that is the case => no solution

anonymous · Answer

the problem states that x is greater than or equal to 0. so i would assume its 0. i just couldnt add in the equal to symbol

anonymous · Answer

next time type: >=  or <=
everybody will understand :)
if <= then 2 solutions:
0 and 2pi

anonymous · Answer

okay thanks for the tip and answer

anonymous · Answer

welcome!

myininaya · Answer

sinxcosx=sinx
sinxcosx-sinx=0
sinx(cosx-1)=0
sinx=0 cosx-1=0
sinx=0  cosx=1
x=0         x=0
x=pi        x=2pi
x=2pi

myininaya · Answer

you guys missed a solution

anonymous · Answer

isnt it just 0 and 2pi?

myininaya · Answer

and pi

anonymous · Answer

oh, alright thanks, would have missed that